In this example we are going to create a function which will count the number of occurrences of each character and return it as a list of tuples in order of appearance. For example,
ordered_count("abracadabra") == [('a', 5), ('b', 2), ('r', 2), ('c', 1), ('d', 1)]
The above is a 7 kyu question on CodeWars, this is the only question I can solve today after the first two fail attempts.
I am supposed to start the Blender project today but because I want to write a post for your people I have spent nearly an hour and a half working on those three python questions on CodeWars, I hope you people will really appreciate my effort and will share this post to help this website to grown.
def ordered_count(input): already =  input_list = list(input) return_list =  for word in input_list: if(word not in already): return_list.append((word, input_list.count(word))) already.append(word) return return_list
The solution above is short and solid, hope you like it.